Math mini-contest problem for Day 7 on D.Buzz for April 2021 ๐
Math problem for Day 7 on D.Buzz for April 2021 ๐
Holovision must store "The Source" - which can potentially provide limitless energy - into a tesseract whose enclosed hyperspace is 8 metersโด. What is the surface area of the tesseract that can contain The Source?
0
0
0.000
My answer is "No Solution".
I have no way of even knowing how to solve this problem and the sci-fi just throws me off. A Tesseract, hyperspace and etc? Whatever I go with the simplest thing that comes to my mind.
I'm sorry that the problem is not interesting for you. ๐ฐ From my perspective, it is still in geometry that may be asked in high school math contests. ๐
Ok wild ass guess. If I want to find the edge length of a square I would square, a cube I would cube, so let's assume this holds and we can ^(1/4) . The edge length of the terrsecat is (8)^(1/4) or 1.68. The surface area in real space is 6x1.68x1.68 = 16.97 in real space.
you're close! only the number of faces has to be scaled up: while it's 6 faces in 3D, it has 24 faces in 4D. Pretty hard to image...
Damn and i was thinking it was time for the last d
A = 24 a^2, where edge length a = fourth-root of the volume = 8 ^(1/4) = 1.682 => The surface area is 67.882.
Answer for Day 7 Math problem
Solution
Let's get started with some facts:
To get the side length of the tesseract, we just get the fourth root of the enclosed hyperspace of the tesseract.
We can now directly solve for the surface area of the tesseract given its side length.
Winner: @minus-pi ๐
The award of 1 HIVE has been sent to @minus-pi's Hive account. ๐ฐ
Mentions: @holovision, @ahmadmanga (@ahmadmangazap), @eturnerx (@eturnerx-dbuzz), @dkmathstats, @paultactico2, and @appukuttan66 ๐ค
Special mentions: @dbuzz, @chrisrice, @jancharlest, and @mehmetfix ๐คฏ