This is the practice problem for my Math mini-contest 😎

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(Edited)
This is my practice problem (see image) for my Math mini-contest for active D.Buzz members! 😅

Rules at https://peakd.com/@savvyplayer/my-plan-for-the-math.
 



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27 comments
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@podewils

Thanks for reblogging and upvoting my post! 🙂 Since you are an active D.Buzz member, you are qualified to answer the Math problem, for which you will get 1 HIVE as reward if your answer is correct! 😁

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(Edited)

I wanted to put the "1 HIVE as prize for the first reply with the correct answer" on the post, but the 280-character limit got in the way. However, since I needed to reveal the correct answer (which is 4 and -3 or vice versa), I can no longer give the prize. Sorry! 🙁

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I think i am active on #dbuzz, but math is not for me, just if i have to calculate money 🤣🤣

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Maybe you can tag someone who you think can solve the Math problem! 🤔😅

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@chrisrice

Maybe your skills will allow you to correctly solve this Math problem! 😆😅

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My skills in the math department aren't very good 😬

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Must... Find.. Time.. to .. read.. email.

  • 99+ notifications 😅

    Posted via D.Buzz
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Maybe 90+ of your notifications are just upvotes! 😆

Oh wait... this is another notification for you! 🤣

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I don't receive very many upvotes 😬

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How about my 0.1% upvotes? 🤔 Don't they show up on your notifications? 🤔 Or, were my votes too few to significantly increase your notifications? 🤔🤔

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Hmmm, most of the things I notice are comments.. that's wierd.

  • Maybe I have notif blinders on 😕

    Posted via D.Buzz
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It depends on the frontend you are using that determines if upvotes with negligible value (zero rshares or close to it) are displayed. #Ecency displays them, while #DBuzz does not. 🤔

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Wierd, I didn't know that!

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What do you mean with "wierd"? 🤔

It sure sounds weird! 😆😂🤣

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Yup, it's weirder than weird.. it's:

----> Wierd 😅

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If it sum it all up to infinity, the answer will come up to be approximately 4 (gets closer and closer every iteration).

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I don't know if I can accept that answer. 🤔 Please examine the problem further for a better answer. Thanks! 😁

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Expanding x = the above question.

  1. Rewrite into x = sqrt(12+x) because sqrt(12+sqrt(12+...)=x
  2. Expand to x^2 -x-12 = 0
  3. Rewrite as (x-4)(x+3)
  4. x=4 or x=-3.
  5. If we exclude imaginary numbers, x=4.
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Why would x = -3 be imaginary for the final answer? It being negative will not cause the radicals to be imaginary. It will still produce a real value for the every radical (sqrt(12 + x) where x is -3). 🤔🕵️‍♂️🔬😅

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It was a mistake. Basically was expanding it as squares and thought of imaginary numbers. Basically x=-3 is impossible given the normal question provided above. While it is possible for x=-3, it is almost unrealistic as sqrt(12)=3.46. So anything you add after is a positive number.

(3i)^2 = -3 for my mistake.

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I don't know if I should continue accepting answers for the problem, because I already revealed the correct answer indirectly. 🤔

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I think the biggest problem was I didn't know exactly what you wanted. Did you want an answer? Did you want all possible solutions? Do we need to explain how to get the answer?

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I want the correct answer. The solutions and explanations are unnecessary. I would just say that your answer was incomplete. 😐

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What was the actual answer? At least according to my logic, the math comes out to x=4 or x=-3. -3 doesn't make sense but could also be a valid answer. I don't think any other answers match.

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The actual answer is "4 or -3" (or vice versa). There are two roots of a radical with an even index, and both of them must be specified in the final answer. There is one answer with two values. 😐

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By the way, thank you for reminding me that. I have now included on the official rules that solutions or explanations are not necessary to be posted with the answer. 🙂

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