Math mini-contest problem for Day 11 on D.Buzz 😎
Math problem for Day 11 😎
In a horse race, holovision's intelligent camera counts horses with human riders. However, the camera malfunctioned, so it instead counted 170 feet and 50 heads, including horses without riders but not riders without horses. How many riders are there?
0
0
0.000
No solution as there is not enough information.
Question is too missing too much information: Feet exist on both Horses and Humans. We do not know if it only includes horses feet or just human feet. Also for each count by the machine, does a horse + rider count as 6 feet(both rider+horse), 4 feet (horse only) or 2 feet(rider).
The number of heads each human and horse has is in parity. The combination of horses and riders has to equal 50 but human quantity has to be a smaller number since the combination of human and horse feet is 170; horses have twice as many feet as humans and riders without horses don't count.
I am probably missing something though. Just like wild horses @savvyplayer seems to be trying to break my spirit by randomly invoking no solution problems. I want to believe there should always be an answer no matter how absurd the question seems.
Note that it should be assumed that horses have 4 feet and humans have 2 feet
excluding mutations and amputations. 😅There is not enough typing room for a 280-character buzz to include all details
from all multiverses known to @holovisionthere. 😅15 riders.
Posted via D.Buzz
Working here:
h + r = 50
4h + 2r = 170
35 + 15 = 50
140 + 30 = 160
I had guests so I plugged numbers in my head until it worked. 40/10 then 30/20 and then 35/15.
Posted via D.Buzz
Brute forcing felt weird. I did it once via h and then again via r as redemption.
Posted via D.Buzz
@holovision might want to recommend that you post your picture about your solution on the Hive Stock Images community. 🤔😅
I'll look at this tomorrow if I have time to see if there's a solution. Or at least talk myself into believing there's a solution. I might still be busy until the weekend.
It's not a malfunction, it's an unanticipated new feature.😎
Can't sleep even though I am tired.😩
I think @eturnerx-dbuzz is right. Replying for @ecency points. 😊 35 horses and 15 of those horses have riders.
Horses have 1 head each. Riders have 1 head each. At least that seems to be right in my fatigued state.
horses + riders = 50
Horses have 4 feet. Riders have 2 feet. Thankfully @savvyplayer clarified that
since that's not true on every planet.r + h = 50
2r + 4h = 170
2r + 4h =170
-2(r + h) = 2(50)
2h = 70 / 2 = 35 horses a.ka. 35 horse heads with 140 horse feet. 15 rider heads with 30 feet.
You just had a maximum of 5.00 #Ecency Points from making that comment! 😅
Answer for Day 11 Math Problem 😎
Solution
The problem is under systems of linear equations in (elementary) algebra.
Let c = horses with riders
Let h = horses without riders
Equation 1 (referring to feet): 6c + 4h = 170
Equation 2 (referring to heads): 2c + h = 50
(Equation 3) = (Equation 1) - 3 * (Equation 2)
h = 20
(Equation 4) = (Equation 2) * 4 - (Equation 1)
2c = 30
c = 15
According to Equation 4, there are 15 riders riding horses. Therefore, there are 15 humans paired with horses. The original problem says that horses without riders are not counted.
Winner: @eturnerx-dbuzz 🏅
1 HIVE has been sent to @eturnerx-dbuzz's Hive account. 💰
We got a participant whose Hive account is loyal to D.Buzz by looking at his username! Anyway, it does not matter if the answer was obtained using guessing, because in this mini-contest, the solution is not required to win! 😎
Mentions: @holovision, @jfang003, and @ahmadmanga (@ahmadmangazap)
Special mentions: @chrisrice and @jancharlest 🤯
@eturnerx (@eturnerx-dbuzz)
Thanks a lot for your upvote worth more than $1! It will definitely help me
buy more Splinterlands cards! 😀😅