Linear Inequalities [Math]

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Hi everyone. In this educational math post I cover the topic of linear inequalities. This topic does build upon solving linear equations. Linear inequalities can be taught as early as grade nine but it is usually taught in grade twelve advanced functions at least in my area.


Pixabay Image Source

 

Review Of Solving Linear Equations


Before getting into solving linear equations I want to review solving linear equations.

Example One

Solve for x in x + 2 = 5.

Think of this question as something plus two equals five. The value of x is 3.

 

Example Two

What is x in 3x = 9?

Three times something is nine. For this question, the answer is 3.

 

Example Three

Determine the value of x in 2x - 1 = 5?

Think of this one in steps. Something minus one equals five. This 2x quantity is equal to 6. Two times something equals three. The answer for x is 3.

 


Pixabay Image Source

Solving Linear Inequalities


Instead of equal to you can use inequality signs such as less than (<) or greater than (>). There is also less than or equal to (≤) and greater than or equal to (≥). Remember that you read from left to right.

The inequality x > 7 reads as x is a number greater than seven.

The inequality x < -2 reads as x is a number less than negative two. Another way to think of this is that x is more negative than -2.

For x ≥ 5, it is x greater than 5 or x is equal to 5.

With x ≤ -1, it is x less than -1 or x is equal to -1.

 

For the images I use this desmos website & screenshot.

Example One

Solve for x in x - 1 < 3.

Solving for x here is not much different than the case with the equal sign. Isolate for x by add one to both sides. This gives the answer of x < 4.

In the screenshot the blue line shades everything on the left of positive 4. As x is less than 4 there is an open circle at 4 to indicate that x cannot equal to four. I have to set the right end to an open circle.

example_one.PNG

 

Example Two

In x ÷ 2 ≥ 5 solve for x.

Multiply both sides by two to undo the division on the left side. The answer ends up being x ≥ 10.

In the screenshot image below the solution for x includes the number ten as indicated by the filled dot as well as everything above ten on the number line.

example_two.PNG

 

Example Three - Dividing By A Negative Number

In -3x ≥ 27 solve for x.

Divide both sides by negative 3. Whenever you multiply or divide by a negative number with an inequality you have the change the direction of the inequality sign. Twenty-seven divided by negative three is negative nine on the right side. The answer here is x ≤ -9.

An alternative solution would be moving the negative three x from the left side to the right side. See the math image below (Quicklatex used).



 

The screenshot image shows the solution of x being less than or equal to negative nine. Note that the screenshot only covers so much. Assume that the left part of the line continues on forever.

example_three.PNG

 

Example Four - Multiply By A Negative Number

Solve for x in -x ÷ 10 < 2.

Multiply both sides by negative ten. Don't forget to switch the direction of the inequality sign. The answer is x > -20. This is x being greater than negative twenty.

 

The number line goes from negative 20 with an open dot and to the right all the way to positive infinity.

example_four.PNG

 


Pixabay Image Source

Thank you for reading.

Posted with STEMGeeks



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Thank you for another math lesson.

!discovery 31

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No problem. Thank you for your support as usual.

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Thank you for the lesson, it was so understandable and well detailed.

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Hello friend, very educational examples of equations and inequalities, greetings and thanks for sharing.

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