SOLUTION TO 06/03/2025 MATH CHALLENGE

Hello everyone, it’s another beautiful day to put the brain into work by providing the solutions for the daily math challenge. I’m delighted to share my solution for 06/03/2025 math problem for the day. Without much time being wasted I would like to present and explain in details how I got my solution.

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So, from the question we are asked to find the number of positive 3 digit numbers that exist. So the first thing I did was to assume those 3 positive digits; X, Y and Z. And for the products of the digits X, Y and Z to be odd, then all digits between 1 to 9 must be odd also. This is because if any even number is introduced the product of X, Y and Z might be even.

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Having established that fact, the next thing I did was to figure out the possible values for X, which falls between the range 1 to 9. That is to say that X belongs to that set of odd numbers {1, 3, 5, 7, 9}. I went further to get the total number of elements in set X ie n(X) which gives me a single value 5. Same approach I used to obtain the set of Y and also the number of elements in set Y and same for Z.

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After obtaining all the number of elements for each digits, I proceeded to find the products of the number of elements for X, Y and Z, which finally gives us the product of the 3 positive digits to be 125 (which is an odd number).
See below the complete process:

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Tools Used:
Graphics Tab/Pen
Laptop and
Mirror Online Whiteboard

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